Skip to content
Free public beta until December 4, 2026: every course is open, no card needed. After that, the first chapter of each course stays free and full access is a one-time $39 ($19 for up to 100 founding members chosen for helpful feedback). Your progress is kept. How the beta works

line integral of a vector field (work)

The integral \int_C \mathbf{F}\cdot d\mathbf{r}, adding up the component of a vector field along a curve's direction of travel — physically, work.

With C parametrized by \mathbf{r}(t), t\in[a,b], the line integral of a vector field is \int_C \mathbf{F}\cdot d\mathbf{r} = \int_a^b \mathbf{F}(\mathbf{r}(t))\cdot \mathbf{r}'(t)\,dt. Only the part of \mathbf{F} pointing along the curve's own direction of travel contributes; a force perpendicular to motion does no work. Unlike the scalar line integral, this one depends on orientation: reversing C's direction negates \mathbf{r}'(t) at every point and hence negates the whole integral, \int_{-C}\mathbf{F}\cdot d\mathbf{r} = -\int_C\mathbf{F}\cdot d\mathbf{r}.

Examples

  • For \mathbf{F}(x,y)=(y,x) along \mathbf{r}(t)=(t,\,t^2), 0\le t\le1: \int_C \mathbf{F}\cdot d\mathbf{r} = 1.

Read the full section →
Graph settings

Calculator