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Create a free account to open Overfitting, regularization, and evaluation. The free chapters of Deep Learning / Neural Networks stay readable without one.

Chapter 0 wrap-up

Readiness review

Closing thought

Every idea in this chapter points at one stubborn matrix. The quarter-turn rotation of the plane moves every nonzero vector off its own line, so it has no real eigenvector. Its characteristic polynomial is \lambda^2+1, which has no real roots. The old toolkit of basis, rank, similarity and eigenvalues still applies to it. It needs a larger number system to finish the job.

You can now factor that polynomial over \mathbb C as (\lambda-i)(\lambda+i) and read off the conjugate pair \pm i. You can also tell when a real polynomial must keep a quadratic factor over \mathbb R but splits completely over \mathbb C. Chapter 1 asks a question these numbers raise. Does a vector space need real scalars at all? The answer is no: any number system where you can add, subtract, multiply and divide will do.

Chapter review

One practice set per topic this chapter taught β€” same fixed, ungraded ladders as the practice panels inside each section.

Practice: Complex numbers and polynomials (2 problems Β· doesn’t affect your progress)

Given z = a+bi, the complex conjugate \overline z is obtained by

Correct! πŸŽ‰ Not quite.

Right on try — credit. Right — the answer had already been shown, so no credit this time. Next try is worth Answer shown after three tries — this one no longer earns credit. You chose to see the answer — this one earns no credit.

That negates z entirely (-z), not the conjugate β€” the real part of a conjugate never changes.

The real part stays exactly the same under conjugation; only the imaginary part's sign flips.

Swapping the parts is a different operation entirely and isn't what conjugation means.

Why

\overline{a+bi} = a-bi β€” only the imaginary part's sign changes.

Flipping the sign of the imaginary part only

The multiplicity k of a root r is defined as

Correct! πŸŽ‰ Not quite.

Right on try — credit. Right — the answer had already been shown, so no credit this time. Next try is worth Answer shown after three tries — this one no longer earns credit. You chose to see the answer — this one earns no credit.

Term count has nothing to do with how many times a particular root repeats.

Multiplicity describes a ROOT's repetition, not how a coefficient happens to look.

Degree is the polynomial's overall size β€” a degree-5 polynomial can have a root of multiplicity 1, 2, 3, 4, or 5.

Why

Multiplicity is exactly how many times (x-r) divides out before a nonzero remainder appears.

(x-r)^k divides evenly but (x-r)^{k+1} does not

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