Recipe
Build a derivative from the definition
Use when: you're asked for f'(x) (or f' at a specific point) and no shortcut rule is available yet
Goal: a simplified expression for f'(x), or its exact value at one point, with the limit already taken
Taught in The definition of the derivative
-
1
Substitute x+h for every x in the formula for f.
Example
For f(x)=x^2-4x: f(x+h)=(x+h)^2-4(x+h).
Why: the difference quotient needs the function's value one step away from x, and this is the only way to get it without a shortcut rule.
-
2
Compute f(x+h)-f(x), then expand and collect like terms.
Example
\big[(x+h)^2-4(x+h)\big]-\big[x^2-4x\big] = x^2+2xh+h^2-4x-4h-x^2+4x = 2xh+h^2-4h.
Why: this is the numerator of the difference quotient, and expanding it fully is what exposes the shared factor of h the next step needs.
-
3
Every remaining term should carry a factor of h; factor it out and cancel.
Example
\dfrac{2xh+h^2-4h}{h}=\dfrac{h(2x+h-4)}{h}=2x+h-4 for h\neq0.
Why: if a term is left over with no h factor, either the expansion or the subtraction in Step 2 has an error. This is the built-in check.
-
4
Take the limit of the simplified expression as h shrinks to 0.
- a specific point x=a was asked for — substitute x=a first, then let h\to0 (or do both at once).
- the general derivative function f'(x) was asked for — let h\to0 while keeping x as a variable.
Why: the simplified form from Step 3 survives substituting h=0 without dividing by zero, which is the entire reason Steps 2–3 existed.
Common mistakes
- Substituting x+h into only part of the formula, missing a term.
- Forgetting to distribute the minus sign when subtracting f(x).
- Setting h=0 before simplifying, which reproduces the original 0/0.
- Reporting the unsimplified difference quotient as if it were already the derivative.