Recipe
Find W(x) with Abel's formula
Use when: you know a linear homogeneous equation's coefficient p(x) and one value W(x_0), but not y_1,y_2 themselves
Goal: an explicit formula for W(x) on the whole interval, without ever finding y_1,y_2
Taught in Abel's formula
Quick recipe
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1
Divide every term by the coefficient of y'' so the equation reads y''+p(x)y'+q(x)y=0, then read p(x) straight off the coefficient of y'.
Example
For 2y''+4y'+6y=0, divide every term by 2: y''+2y'+3y=0, so p(x)=2.
Why: Abel's formula is stated for the standard form with a leading coefficient of exactly 1 — reading p off the un-normalized equation would scale it wrong.
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2
Compute \int_{x_0}^{x} p(t)\,dt; how much work this takes depends on whether p is constant or genuinely varies.
Example
With p(x)=2 constant and x_0=0: \int_0^x 2\,dt=2x.
- p(x) is a constant — the integral is just that constant times (x-x_0).
- p(x) genuinely varies with x — integrate it as an ordinary function of x.
Why: this integral is exactly the exponent Abel's formula needs — it's the total decay p contributes between x_0 and x.
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3
Form e^{-\int_{x_0}^x p(t)\,dt}.
Example
e^{-2x}.
Why: Abel's formula derives W as the solution of the decay equation W'=-pW, and the minus sign belongs to that equation, not to p itself — dropping it flips growth and decay.
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4
Substitute the given W(x_0) to get the explicit formula for W(x).
Example
With W(0)=4: W(x)=4e^{-2x}.
Why: x_0 is exactly where the formula's constant of integration gets pinned down by the one piece of data the problem actually hands you.
Common mistakes
- Reading p(x) off an equation before dividing to standard form (e.g. reading p=4 straight from 2y''+4y'+6y=0 instead of the correct p=2).
- Dropping the minus sign in the exponent.
- Using a lower limit x_0 that doesn't match the point where W(x_0) is actually known.
- Trying to find y_1,y_2 explicitly first — Abel's formula is precisely the tool that makes that unnecessary.