Recipe
Write parametric and symmetric equations of a line in space
Use when: you're given a point and a direction vector, or two points, and need the line through them as parametric or symmetric equations
Goal: parametric equations for x, y, z, and, when no direction component is zero, the matching symmetric equations
Taught in Lines in space
Quick recipe
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1
A line's equations always start from one point and one direction, but a problem can hand those over in two different shapes.
Example
Given P_1=(1,0,-2) and P_2=(3,5,-1): \mathbf v=\langle3-1,\,5-0,\,-1-(-2)\rangle=\langle2,5,1\rangle. Take P_0=P_1=(1,0,-2).
- a point P_0 and a direction vector \mathbf v are given directly — use them as they are.
- two points P_1,P_2 are given instead — compute the direction as \mathbf v=\overrightarrow{P_1P_2}, subtracting matching coordinates, and use either point as P_0.
Why: every later step needs exactly one point and one direction vector, whichever form the problem originally handed over.
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2
Read the point's coordinates and the direction's components straight into x=x_0+at,\ y=y_0+bt,\ z=z_0+ct.
Example
x=1+2t,\quad y=5t,\quad z=-2+t.
Why: these three equations are exactly the vector equation \mathbf r(t)=\mathbf r_0+t\mathbf v, read off one component at a time.
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3
Look back at the direction vector's three components from Step 1 before dividing by any of them.
Example
With \mathbf v=\langle2,5,1\rangle, none of the components are zero, so \dfrac{x-1}{2}=\dfrac{y}{5}=\dfrac{z+2}{1}.
- a,b,c are all nonzero — solve each parametric equation for t and set the results equal, \dfrac{x-x_0}{a}=\dfrac{y-y_0}{b}=\dfrac{z-z_0}{c}.
- one of a,b,c is zero — the symmetric form doesn't exist; report the parametric equations only, and give that one coordinate's fixed value directly alongside the remaining ratio.
Why: dividing by a zero direction component is undefined, so symmetric form only exists for a line that isn't parallel to any coordinate plane.
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4
Substitute a specific value of t and confirm the resulting point matches a point the line was supposed to pass through.
Example
At t=1: x=1+2=3,\ y=5,\ z=-2+1=-1, matching P_2=(3,5,-1) exactly.
Why: this catches an arithmetic slip in the direction vector or the point before the equations get used anywhere downstream.
Common mistakes
- Subtracting the two points in the wrong order, which still describes the same line but can look wrong against an answer key.
- Writing symmetric equations when a direction component is zero, dividing by zero without noticing.
- Using a point that isn't actually on the line as P_0.
- Confusing the direction vector's own components with a position vector, when the direction vector's tail location never matters.